4p^2+7p+1=0

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Solution for 4p^2+7p+1=0 equation: 



4p^2+7p+1=0

a = 4; b = 7; c = +1;
Δ = b2-4ac
Δ = 72-4·4·1
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{33}}{2*4}=\frac{-7-\sqrt{33}}{8}
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{33}}{2*4}=\frac{-7+\sqrt{33}}{8}
$

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